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in Physics by (64.8k points)

In the network shown in Fig., find the value of RL such that maximum possible power will be transferred to RL. Find also the value of the maximum power and the power supplied by source under these conditions.

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We will remove RL and find the equivalent Thevenin’s source for the circuit to the left of terminals A and B. As seen from Fig.  Vth equals the drop across the vertical resistor of 3Ω because no current flows through 2 Ω and 1 Ω resistors.

 

Since 15 V drops across two series resistors of 3 Ω each, Vth = 15/2 = 7/5 V. 

Thevenin’s resistance can be found by replacing 15 V source with a short-circuit. 

As seen from Fig. , Rth = 2 + (3 || 3) + 1 = 4.5 Ω. Maximum power transfer to the load will take place when RL = Rth = 4.5 Ω.

Maximum power drawn by RL = Vth 2 /4 × RL = 7.52 /4 × 4.5 = 3.125 W. 

Since same power in developed in Rth, power supplied by the source = 2 × 3.125 = 6.250W.

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