Apply Thevenin’s theorem. For this RL has to be detached from nodes A and B. Treat O as the reference node.
VA = 60 V, VB = VC + 2 = 50 + 2 = 52 V
Thus, VTH = VAB = 8 volts, with A positive w.r. to B, RTH = (60||40) + (50||50) = 49 ohms
Hence, for maximum power, RL = 49 ohms
With this RL, Current = 8/98 amp = 0.08163 amp
Power to Load = i2 RL = 0.3265 watt
