Question

Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by 

(a) A, B and C 

(b) B, C and F 

(c) A, B and F 

(d) A, C and F

Answer 1

Correct option (b) B, C and F     

Explanation:

At the start all the boys have equal number of cards, as shown below:

A	10
B	10
C	10
D	10
E	10
F	10

Now, F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B:

A	8
B	13
C	12
D	10
E	10
F	7

B gives 6 to D who passes on 1 to E. 

A	8
B	7
C	12
D	15
E	11
F	7

 Number of cards with D and E = 15 + 11 = 26

We can see that number of cards with B, C and F = 7 + 12 + 7 = 26