Sarthaks Test
0 votes
in Physics by (55.0k points)

A pipe has an outside diameter of 25 mm, an inside diameter of 15 mm and length 0.40 m and it supports a compressive load of 40 kN. The pipe shortens by 0.5 mm when the load is applied. Determine (a) the compressive stress, (b) the compressive strain in the pipe when supporting this load. 

1 Answer

+1 vote
by (66.4k points)
selected by
Best answer

Compressive force F = 40 kN = 40000 N,

and cross-sectional area A = π/4 (D2 − d2)

where D = outside diameter = 25 mm and 

d = inside diameter = 15 mm. Hence

(a) Compressive stress

(b) Contraction of pipe when loaded, 

x = 0.5 mm = 0.0005 m, and original length 

L = 0.40 m. Hence, compressive strain,

ε = x/L = 0.0005/0.4

= 0.00125 (or 0.125%)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.