Compressive force F = 40 kN = 40000 N,
and cross-sectional area A = π/4 (D2 − d2)
where D = outside diameter = 25 mm and
d = inside diameter = 15 mm. Hence
(a) Compressive stress
(b) Contraction of pipe when loaded,
x = 0.5 mm = 0.0005 m, and original length
L = 0.40 m. Hence, compressive strain,
ε = x/L = 0.0005/0.4
= 0.00125 (or 0.125%)