For growth ; 5 = Im (1 −e −0.3/λ) ...(i)
For decay; 5 = Im e −0.3/λ
Equating the two, we get, Ime −0.3/λ = (1 −e− 0.3/λ)Im
or 2e−0.3/λ = 1
∴ e −0.3/λ = 0.5 or λ = 0.4328
Putting this value in (i), we get,
5 = Im = e 0.3/0.4328 or Im = 5 e + 0.3/0.4328 = 5 × 2 = 10 A.
Now, Im = V/R
∴ 10 = 230/R or R = 230/10 = 23 Ω (approx.)
As λ = L/R = 0.4328 ; L = 0.4328 × 23 = 9.95 H