The beam and its loads are shown in Figure At equilibrium,
RA + RB = 2.5 + 5.5 = 8.0 kN (1)
Taking moments about A, clockwise moments = anticlockwise moment,
i.e. (2.5 × 2.0) + (5.5 × 3.0) = 4.0 RB
or 5.0 + 16.5 = 4.0 RB
from which, RB = 21.5/4.0 = 5.375 kN
From equation (1), RA = 8.0 − 5.375 = 2.625 kN
Thus the reactions at the supports at equilibrium are 2.625 kN at A and 5.375 kN at B