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Determine the end reactions for the simply supported beam of Figure  which is subjected to an anti-clockwise couple of 5 kN m at the point C

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Taking moments about B gives:

RA × 3 m = 5 kN m ........(5.4)

from which, RA = 5/3 kN

or RA = 1.667 kN

Resolving forces vertically gives:

i.e. RA + RB = 0

from which, RB = −RA = −1.667 kN

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