Given PF = FD = 200 mm = 0.2 m; DK = 40 mm = 0.04 m; BF = 100 mm = 0.1 m; m = 6 kg; M = 150 kg; r = JG = 180 MM = 0.18 M; f = 20 N
(i) Equilibrium speed
Let N = Equilibrium speed.
From the equilibrium position as shown in Fig, We find that tat height governor,
IM = IN - MN = FH - JF = 0.1286 - 0.0114 = 0.1172 m
ID = 2 x IN = 2 x FH = 2 x 0.1286 = ) = 2572 m
We know that centrifugal force,
Now taking moments about I,