Here, A and B are symmetric matrices, then A′ = A and B′ = B
Now, (AB − BA)′ = (AB)′ − (BA)′ (∵(A − B)′ = A′ − B′ and (AB)′ = (B′A′)
= B ′A′ − A′B′ = BA − AB (∵ B′ = B and A′ = A)
= −(AB − BA)
⇒(AB − BA)′ = −(AB − BA)
Thus, (AB − BA) is a skew-symmetric matrix.