Since A, B, C are all square matrices of order 2, and CD – AB is well defined, D must be a square matrix of order 2.
By equality of matrices, we get
2a + 5c – 3 = 0 ... (1)
3a + 8c – 43 = 0 ... (2)
2b + 5d = 0 ... (3)
and 3b + 8d – 22 = 0 ... (4)
Solving (1) and (2), we get a = –191, c = 77.
Solving (3) and (4), we get b = – 110, d = 44.
Therefore