Series combination of 1 Ω and 3 Ω resistance is in parallel combination with 6 Ω .Their equivalent resistance is
Now, 3.6 Ω 2.4 Ω and 3 Ω are in series, their equivalent resistance be
Rs = R1 + R2 + R3
= 3.6 + 2.4 + 3 = 9 Ω
Hence, the current flowing through the circuit is