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Find the current flowing through the following electric circuit.

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Series combination of 1 Ω and 3 Ω resistance is in parallel combination with 6 Ω .Their equivalent resistance is 

Now, 3.6 Ω 2.4 Ω and 3 Ω are in series, their equivalent resistance be 

Rs = R1 + R2 + R3

= 3.6 + 2.4 + 3 = 9 Ω

Hence, the current flowing through the circuit is

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