Question

Draw a schematic diagram of an electric circuit consisting of a battery of five 2 V cells, a 20 Ω resistor, a 30 Ω resistor, a plug key, all connected in series. Calculate the value of current flowing through the 20 Ω resistor and the power consumed by the 30 Ωresistor.

Answer 1

R_eq = 20 + 30 = 50 Ω

Here, V = 5 x 2 V = 10V, Total Resitance, R = 20Ω + 30Ω = 50Ω

Current through both 20 Ωand 30 Ω= I =V/R = 10/50 A = 0.2 A

Power consumed by 30 Ω = I²R = (0.2)² x 30 =1.2W