Since each trial in this problem is Bernoulli trials, therefore we can apply binomial distribution as
Now probability distribution table is
X or xi |
0 |
1 |
2 |
3 |
4 |
P(X) or pi |
625/1296 |
500/1296 |
150/1296 |
20/1296 |
1/1296 |
Now mean E(X) = ∑pixi = 0 x 625/1296 + 1 x 500/1296 + 2 x 150/1296 + 3 x 20/1296 + 4 x 1/1296
= (500 + 300 + 60 + 4)/1296 = 864/1296 = 2/3