(a) u = – 9 cm, f = 10 cm
As, 1/v - 1/u = 1/f
∴ 1/v = 1/f + 1/u = 1/10 + 1/-9
= (9 - 10)/90 = - 1/90
∴ v = - 90cm
∴ Magnification = v/u = 90/9 = 10.
In the virtual image, area of each square = (10 × 10 × 1) mm2
= 100 mm2 = 1 cm2.
(b) Magnifying power of the lens = d/u = 25/9 = 2.8.
(c) No. The magnification produced by a lens and its magnifying power are different. The magnitude of magnification is given by v/u and magnifying power is 25/u .
Only when the image is located at the near point (i.e. |v| = 25 cm) are the two quantities equal.