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The line joining two points A(2, 0) and B(3, 1) is rotated about A through an angle 15° in the counter clock sense. Find the equation of the line in the new position and the coordinates of the new position of B.

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See Fig.  Let ∠XAB = α so that

tanα = 1 -0/3 - 2 = 1 or α =  45°

Since ∠XAC =  α + 15° = 60°, the equation of the line AC (point C is the new position of point B) is

y - 0 tan 60°(x - 2) = √3(x -2)

Therefore, equation of the line AB in its new position is

√3x - y - 2√3 = 0

The value of x = 2 − 1/ √2 gives the position of point B, when (bar)AB is rotated about point A through angle 15° in clockwise sense.

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