Question

ABCD is a trapezium such that AB and CD are parallel and BC ⊥ CD. If ∠ ABD = θ, BC = p and CD = q then AB is equal to :

(A) ((p² + q²)sinθ)/(pcosθ + qsinθ)

(B) (p² + q²cosθ)/(pcosθ + qsinθ)

(C) (p² + q²)/(p²cosθ + q²sinθ)

(D) ((p² + q²⁾sinθ)/(pcosθ + qsinθ)²

Answer 1

Correct option (A) ((p² + q²)sinθ)/(pcosθ + qsinθ)

Explanation:

Let AB = x