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in Co-ordinate geometry by (63.5k points)

In acute angled triangle ABC, a semicircle with radius ra is constructed with its base on BC and tangent to the other two sides   rb and rc are defined similarly. If r is the radius of the in circle of triangle ABC, then prove that, 2/r = 1/ra + 1/rb + 1/rc.

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3/r - 1/r = 1/ra + 1/rb + 1/rc

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