y2 + 2 = 3y
y = 1, 2
AC = 1, AB = 2
BD/CD = (x2 + 1)/2x
(BD + CD)/CD = (x2 + 1 + 2x)/2x
√3/CD = (x + 1)2/2x
CD = 2√3x/(x + 1)2 = b/(c + b)(√3)
Similarly BD = √3(x2 + 1)/(x + 1)2
2√3x/(x + 1)2 = 1/√3
6x = (x + 1)2 ⇒x2 + 1 – 4x = 0
⇒ x1 + x2 = 4
tan(A1/2) + tan(A2/2) = 2x1/1 + 2x2/1 = 8