Correct option (C) −2
Explanation:
BD = 1/2BC
Pythagoras theorem in ∆BAD
c2 + (AD)2 = (BD)2
c2 + 1/4(2b2 + 2c2 - a2) = a2/4
⇒ a2 = b2 + 3c2
tanA/tanB = sinA/sinB x cosB/cosA
= a/b((a2 + c2 - b2)/2ac) (2bc/(b2 + c2 - a2))
= (a2 + c2 - b2)/(b2 + c2 - a2) = - 2