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in Co-ordinate geometry by (63.5k points)

In a ∆ ABC, a semicircle is inscribed, whose diameter lies on the side C. Then the radius of the semicircle is Where ∆ is the area of the triangle ABC.

(A) 2∆/(a + b)

(B) 2∆/(a + b - c)

(C) 2∆/s

(D) c/2

1 Answer

+1 vote
by (64.8k points)
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Best answer

Correct option (A) 2∆/(a + b)

Explanation:

DF = ?; OE = r; OD =  r/sin(A/2)

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