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If cosA + cosB + 2cosC = 2 then the sides of the ∆ ABC are in (A) A.P.

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in Co-ordinate geometry by (63.5k points)

If cosA + cosB + 2cosC = 2 then the sides of the ∆ ABC are in 

(A) A.P. 

(B)G.P. 

(C) H.P. 

(D)None

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1 Answer

+2 votes
by (64.8k points)
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Best answer

Correct option (A) A.P   

Explanation:

cosA + cosB = 2(1 – cosC)

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