Question

Simplify: (-i)^{4n + 1}, where n is a positive integer.

Answer 1

(-i)^{4n + 1} 

= (i². i)^{4n + 1} 

= (i³)^{4n + 1}

= i^{12n + 3}

= i¹²ⁿ. i³

= (i⁴)³ⁿ. i². i

= 1. (-1). i

= -i.

Answer 2

Can be written as (--i)^4n.(-i)

=(-i^2)^2n . (-i)

=(-1)^2n.(-i)

=1. (-i)=-- i

Comments

-- = -  pls read as minus, typing error.

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Improve your typing error.