**Let **

T_{1} = Tension in the tight side of the belt

T_{2} = Tension in the slack side of the belt

V = Velocity of the belt in m/sec.

= πDN/60 m/sec, D is in meter and N is in RPM

P = Maximum power transmitted by belt drive

The effective tension or force acting at the circumference of the driven pulley is the difference between the two tensions (i.e., T_{1} – T_{2})

Effective driving force = (T_{1}–T_{2})

Work done per second = Force X Velocity

= F X V N.m

= (T_{1}–T_{2})X V N.m

Power Transmitted = (T_{1}–T_{2}).V/1000 Kw

(Here T_{1 }& T_{2 }are in newton and V is in m/sec)

**Note:**

1. Torque exerted on the driving pulley = (T_{1}–T_{2}).R

Where R_{1} = radius of driving pulley

2. Torque exerted on the driven pulley = (T_{1}–T_{2}).R_{2}

Where R_{2} = radius of driven pulley.