Given that,

D_{1 }= Diameter of the driver = 200mm = 0.2m

T_{1}/T_{2} = 1.2

Since between T_{1} and T_{2}, T_{1} is always greater than T_{2},

Hence T_{1} = 240KN

N_{1} = Speed of the driver in R.P.M. = 60PRM

P = ?

We know that

T_{1}/T_{2} = 1.2

T_{2} = T_{1}/1.2 =240/1.2 = 200KN

V = Velocity of the belt in m/sec

= πDN/60 m/sec, D is in meter and N is in RPM

= (3.14 X 0.2 X 60)/60 = 0.628 m/sec

P = (T_{1 }- T_{2}) X V

P = (240 - 200) X 0.628

**P = 25.13KW**