Given that,
D1 = Diameter of the driver = 200mm = 0.2m
T1/T2 = 1.2
Since between T1 and T2, T1 is always greater than T2,
Hence T1 = 240KN
N1 = Speed of the driver in R.P.M. = 60PRM
P = ?
We know that
T1/T2 = 1.2
T2 = T1/1.2 =240/1.2 = 200KN
V = Velocity of the belt in m/sec
= πDN/60 m/sec, D is in meter and N is in RPM
= (3.14 X 0.2 X 60)/60 = 0.628 m/sec
P = (T1 - T2) X V
P = (240 - 200) X 0.628
P = 25.13KW