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A belt supports two weights W1 and W2 over a pulley as shown in fig If W1 = 1000N, find the minimum weight W2 to keep W1 in equilibrium. Assume that the pulley is locked and µ = 0.25.

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Let the tensions in the belt be T1 and T2 as shown, since the weight W2 just checks the tendency of weight W1 to move down, tension on the side of W1 is larger. 

That is, T1>T2.

Using the relation Ratio of belt tension 

= T1/T2 = eµθ

W1/T2 = e(0.25)(Π)

On solving, T2 = W2 = 456N.

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