**Given data: **

Torque(t) = 300N-m

Coff. of friction(µ) = 0.3

Diameter of Drum (D) = 1m, R = 0.5m

Mass of drum(m) = 20Kg.

Since angle of contact = π rad

Torque = (T_{1} – T_{2}).R

300 = (T_{1} – T_{2}) X 0.5

T_{1}– T_{2} = 600N ...(i)

And, T_{1}/T_{2} = e^{µθ }

T_{1}/T_{2} = e^{(0.3)π }

T_{1 }= 2.566T_{2} ...(ii)

Solving (i) and (ii)

We get,

**T**_{1} = 983.14N

T_{2} = 383.14N

Now reaction on bearing is opposite to the mass of the body, and it is equal to

R = T_{1} + T_{2} + mg

R = 983.14 + 383.14 + 20 X 9.81

**R = 1562.484N.**