Given data:
Torque(t) = 300N-m
Coff. of friction(µ) = 0.3
Diameter of Drum (D) = 1m, R = 0.5m
Mass of drum(m) = 20Kg.
Since angle of contact = π rad
Torque = (T1 – T2).R
300 = (T1 – T2) X 0.5
T1– T2 = 600N ...(i)
And, T1/T2 = eµθ
T1/T2 = e(0.3)π
T1 = 2.566T2 ...(ii)
Solving (i) and (ii)
We get,
T1 = 983.14N
T2 = 383.14N
Now reaction on bearing is opposite to the mass of the body, and it is equal to
R = T1 + T2 + mg
R = 983.14 + 383.14 + 20 X 9.81
R = 1562.484N.