**Correct option (D) (-3,9)**

**Explanation :**

See Fig. Let B = (x, 3x/4) and C = (h, 0). Since B, P and C are collinear, we have

Also

When h = 5/3

Hence, the coordinates of B and C, respectively, are either(4/3,1) and (5/3,0) or (12,9) and (-15,0).

Two cases arise :

**Case 1 : **B = (4/3,1),P = (0,5) and C = (5/3,0)

P is an inside point and B, P and C are collinear.

This implies

Therefore,

BP + PC = 9√10 = BC

Hence

A = (12 - 0 - 15,9 - 0 - 0) = (-3,9)