**Given data: **

Angle of groove(2α) = 30º, α = 15º

Max. Tension(T_{max)} = 2500N

Angle of lap(contact) (θ) = 140º = 140º X (Π/180º) = 2.44 rad

Coefficient of friction (µ) = 0.15 Speed of belt(V) = 2m/sec We know that,

T_{max }= T_{1} =2500N

(TC is neglected, since belt speed is less than 10m/sec)

Ratio of Tension in V-Belt:: T_{1}/T_{2} = e^{µ.θ.cosec α}

2500/T_{2} = e^{(0.15).(2.44).cosec15}

T_{2 }= 2500/4.11

T_{2} = 607.85N ...(i)

(i) Net driving tension = (T_{1}–T_{2})

** = 2500 – 607.85 = 1892.2 N **

(ii) Power transmitted = (T_{1} – T_{2})X V W

** = (2500 – 607.85) X 2 = 3784.3 Watt**