Fewpal
0 votes
26 views
in Physics by (58.6k points)

A train of mass 200KN has a frictional resistance of 5N per KN. Speed of the train, at the top of an inclined of 1 in 80 is 45 Km/hr. Find the speed of the train after running down the incline for 1Km.

1 Answer

+1 vote
by (66.3k points)
selected by
 
Best answer

Given data, Mass m = 200KN, Frictional resistance Fr = 5N/KN, sinθ = 1/80 = 0.0125,

Initial velocity u = 45Km/hr = 12.5m/sec, s = 1km = 1000m

Total frictional resistance = 5 X 200 = 1000N = 1KN ...(i)

Force responsible for sliding = Wsinθ = 200 X 0.0125 = 2.5KN

Now, Net force, F = F – Fr = ma

   2.5 – 1 = (200/9.81)a

a = 0.0735m/sec...(ii)

Apply the equation, v2 = u2 + 2as

v2 = 0 + 2 X 0.0735 X 1000

v = 12.1 m/sec

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...