Fewpal
+1 vote
28 views
in Physics by (57.6k points)

How you evaluate the strength of solid and hollow circular shaft (Tmax)?

1 Answer

+2 votes
by (63.6k points)
selected by
 
Best answer

Strength of a shaft may be defined as the maximum torque which can be applied to the shaft without exceeding allowable shear stress and angle of twist. 

FOR SOLID SHAFT 

From the torsion equation : T/J = τ/R = G.θ/L

Since T = τ.J/R 

= τ.[(πD4/32)/(D/2)] 

= τ.(π/16)D3 

Tmax = (π/16) τmax.D3 ...(i) 

Again since T/J = G.θ/L; T = J.G.θ/L 

= (ÀD4/32).G.θ/L 

Or ; Tmax = (πD4/32).G.θmax/L ...(ii)

Where ; 

Tmax = Maximum torque 

θmax = Maximum angle of twist 

τmax = Maximum shear stress 

Note: The strength of the shaft is the minimum value of Tmax from equation (i) and (ii). And for finding out diameter of shaft we take maximum value of dia obtained from equation (i) and (ii) 

As the same for hollow shaft 

Tmax = (π/16) τmax.(D4 – d4)/D ...(iii) 

= (π/32)(D4 – d4).G.θmax/L ...(iv)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...