Steps:
1. Taking origin at O draw the axes.
2. Cut off OA = σx = 80 kN/m2 and OB = – σy = – 40 kN/m2. Let us choose a suitable scale, say 1 mm = 2 kN/m2
3. Bisect AB at C.
4. With C as centre and CA as radius, draw a circle, which is Mohr’s circle.
5. At C draw a straight line CP making an angle 2θ = 60º with CX.
6. From P draw perpendicular to OX to intersect at Q.
7. Then OQ = σ and PQ = τ
It is found σ = 50 kN/m2 and τ = 52kN/m2
Similarly, at C draw a straight line, CP making an angle 2θ = 240° with CX. From P′ draw perpendicular to OX to intersect at Q′. Then
OQ′ = σ = –10kN/m2 and P′Q′= –52 kN/m2