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If y = 2[x] + 3 = 3 [x – 2] + 5, then find the value of [x + y]

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If y = 2[x] + 3 = 3 [x – 2] + 5, then find the value of [x + y]

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We have 2[x] + 3 = 3[x – 2] + 5

⇒ 2[x] + 3 = 3[x] – 6 + 5

⇒ [x] = 4 fi 4 ≤ x < 5

Also, y = 2[x] + 3 = 2.4 + 3 = 11

Now, [x + y] = [x + 11] = [x] + 11 = 4 + 11 = 15

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