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in Differential equations by (64.8k points)

Find the value of [2015/2] + [2016/4] + [2018/8] + [2022/16] + ....

1 Answer

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Best answer

We have

[2015/2] + [2016/4] + [2018/8] + [2022/16] + ....

= [(2014 + 1)/2] + [(2014 + 2)/4] + [(2014 + )/8] + [(2014 + 8)/16] + .....

= 2014.

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