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in Differential equations by (50.3k points)

Find the range of A = sin2010θ + cos2014θ 

1 Answer

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Now, 0 < sin2010θ  sin2θ ....(i)

and 0 < cos2014θ  cos2θ ....(ii)

Adding (i) and (ii), we get,

0 < sin2012θ + cos2014θ  sin2θ + cos2θ 

⇒ 0 < A  1

Thus, the range of A = (0, 1]

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