Join Sarthaks eConnect Today - Largest Online Education Community!
0 votes
11 views
asked in Physics by (28.3k points)

A cubical block of wood of each side 10 cm long floats at the interface between oil and water with its lower surface 2 cm below the interface. The heights of oil and water column are 10 cm each. The density of oil is 0.8 g cm–3

(a) What is the mass of the block ? 

(b) What is the pressure at the lower side of surface of block ?

1 Answer

+1 vote
answered by (24.7k points)
selected by
 
Best answer

(a) Buoyant force = (mass of liquid displaced) × g

= [10 × 10 × 8 × 0.8 + 10 × 10 × 2 × 1]g

= 840 g

If m is mass of block

mg = 840 g

or m = 840 gm

(b) Pressure at the lower surface of block = pressure at any point on the same level

= 10 × 0.8 × g + 2 × 1 × g

= 10 g = 10 × 9.81

= 98.1 Newton / metre2 .

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Categories

...