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in Physics by (64.7k points)

A cubical block of wood of each side 10 cm long floats at the interface between oil and water with its lower surface 2 cm below the interface. The heights of oil and water column are 10 cm each. The density of oil is 0.8 g cm–3

(a) What is the mass of the block ? 

(b) What is the pressure at the lower side of surface of block ?

1 Answer

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Best answer

(a) Buoyant force = (mass of liquid displaced) × g

= [10 × 10 × 8 × 0.8 + 10 × 10 × 2 × 1]g

= 840 g

If m is mass of block

mg = 840 g

or m = 840 gm

(b) Pressure at the lower surface of block = pressure at any point on the same level

= 10 × 0.8 × g + 2 × 1 × g

= 10 g = 10 × 9.81

= 98.1 Newton / metre2 .

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