(a) Let F be the force applied horizontally such that v1 is the velocity of water in tube A of radius 4.0 cm and v2 equal to 8 m/s is the velocity of water out of tube B of radius 1.0 cm. Let p0 be atmospheric pressure.
∴ At A, v1 = ?, r1 = 4.0 cm, p1 = p0 +F/a
where a is area of cross-section of piston or tube A
At B, v2 = 8 m/s, r2 = 1.0 cm, p2 = p0
Bernoulli’s theorem at A and B gives,
p1 +1/2 ρv12 +hρg = p2 +1/2 ρv22 +hρg
where ρ is density of water and h is height of axis of both tubes from ground level
Equation of continuity at A and B gives