(a) Let F be the force applied horizontally such that v_{1} is the velocity of water in tube A of radius 4.0 cm and v_{2} equal to 8 m/s is the velocity of water out of tube B of radius 1.0 cm. Let p_{0} be atmospheric pressure.

∴ At A, v_{1} = ?, r_{1} = 4.0 cm, p_{1} = p_{0} +F/a

where a is area of cross-section of piston or tube A

At B, v_{2} = 8 m/s, r_{2} = 1.0 cm, p_{2} = p_{0}

Bernoulli’s theorem at A and B gives,

p_{1} +1/2 ρv_{1}^{2} +hρg = p_{2} +1/2 ρv^{2}_{2 }+hρg

where ρ is density of water and h is height of axis of both tubes from ground level

Equation of continuity at A and B gives