0 votes
in Physics by (65.5k points)

A vertical U-tube of uniform area of cross-section contains water upto a height of 60 cm. If the water (ρw = 1000 Kg/m3 ) is depressed on the surface and then released such that the water level moves up and down in both the limbs. Show that the up and down motion of water level is simple hormonic and find its time period. (g = 9.8 m s–2)

1 Answer

+1 vote
by (58.9k points)
selected by
Best answer

Let water level be initially at the positions A and B at a height of 60 cm in the U-tube. If the water level is depressed through a distance y in one of limbs from A to A', water rises in the second limb through y from B to B' so that the difference of level in two limbs, A'B', is 2y.

Pressure difference in two limbs = difference in levels × density of water × g = 2y × ρw × g

Restoring force on liquid = 2y × ρw × g × S

where S is area of cross-section of tube.

If m is mass of liquid of height h in each limb initially, m = 2hS × ρw

If a is acceleration imparted to mass m of liquid due to restoring force, a

As acceleration a is directly proportional to vertical displacement and is directed towards the mean positions A or B, the water level executes S.H.M. Its time period T is given by:

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.