Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.9k views
in Physics by (64.7k points)

The cylinder is removed and the original arrangement is restored. A tiny hole of area S (S<<A) is punched on the vertical side of the container at a height h (h < H/2). Determine:

(i) the initial speed of efflux of liquid at the hole.

(ii) the horizontal distance x travelled by the liquid initially.

(iii) the height hm at which the hole should be punched so that the liquid travels the maximum

distance xm initially. Also calculate xm:

(Neglect the air-resistance in these calculations).

1 Answer

+2 votes
by (58.3k points)
selected by
 
Best answer

 (i) Let vA and vB be velocity of fluids at points A and B.

(ii) Time t taken by liquid to fall through height h under g with zero initial velocity, 

t =√2h/g

Horizontal distance x = vB

(iii) To find height h at which x is max, dh/dx = 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...