(a) Let us consider a cylindrical section at a distance of r and having thickness dr.
The volume of fluid flowing from this section per second
So, the volume of fluid flowing across the section of the tube in unit time
(b) The kinetic energy of the fluid within the volume element of thickness dr
So, the K.E. of fluid within the tube
Integrating, we get
(c) The viscous drag exerts a force on the tube
(d) The pressure difference ΔP is given by
ΔP = P2 – P1 = P
Where P1 = 0 & P2 = P
As we know that
P = Force (F)/ area of section of tube