Correct option (a,c)
Explanation :
The centre of the required circle lies on the line 2x + y - 10 = 0 which is an angular bisector of the lines x + 2 = 0 and 3x + 4y - 50 = 0. Let C(α, 10 - 2α) be the centre of the required circle. Hence
Therefore, the required centre of the circles are (3, 4) and (8, -6), respectively, and their radii are the distances of their centre from the origin which are 5 and 10, respectively. Hence, the circles are
(x - 3) + (y - 4) = 25 and (x - 8) (y + 6)2 = 100
That is,
x2 + y2 - 6x - 8y = 0 and x2 + y2 - 16x + 12 = 0
