Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
18.8k views
in Mathematics by (63.7k points)

If the equation of the plane passing through the intersection of the planes x + 2y + z − 1 = 0 and 2x + y + 3z − 2 = 0 and perpendicular to the plane x + y + z − 1 = 0 is x + ky + 3z − 1 = 0, then the value of k is

(A) 4 

(B) − 4 

(C) 2 

(D) − 2 

1 Answer

+1 vote
by (57.5k points)
selected by
 
Best answer

Correct option is (B) - 4

Explanation :

Let E1 = 0 and E2 = 0 be the given two planes and E = 0 be the required plane. Since E = 0 passes through the line of intersection of E1 = 0 and E2 = 0,

This is perpendicular to the plane x + y + z − 1 = 0.

Therefore

Hence, k = − 4

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...