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The planes E1 ≡ x − y − z − 4 = 0 and E2 ≡ x + y + 2z − 4 = 0 intersect in line L. The plane E1 = 0 is rotated about the line L through 90°. The equation of E1 = 0 in its new position is 

(A) 5x + y − 4z − 20 = 0 

(B) 5x − y + 4z − 20 = 0 

(C) 5x + y + 4z − 20 = 0 

(D) 5x + y + 4z + 20 = 0

1 Answer

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Best answer

Correct option is (C) 5x + y + 4z + 20 = 0

Explanation :

See Fig. 

Let E be the required plane. Therefore

E is perpendicular to E1. This implies

Therefore

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