Substituting y2 = 4x in the given circle equation, we have x2 - 2x + 1 = 0 and hence (1, ± 2) are common points of the two curves. Also at P(1, 2), equation of the tangent to the parabola is
y(2) - 2(x + 1) = 0
⇒ y - x - 1 = 0 ..(i)
The centre and the radius of the circle are (3, 0) and 2√2, respectively. Now, the distance of the centre (3, 0) from Eq. (1) is
Hence, the line provided in Eq. (1) also touches the circle in a similar manner as the two curves touch at Q.