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0 votes
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in Mathematics by (63.8k points)

Match the items of Column I with those of Column II.

Column I Column II 
(A) The distance of the point (2, 5, −3) from the plane 6x − 3y + 2z − 4 = 0 is (p) √105
(B) If the lines 
(x - 1)/2 = (y + 1)/3 = (z - 1)/4 and (x - 3)/1 = (y - k)/2 = z/1
intersect, then the distance between the points (1, −1, 1) and (3, 2k, 0) is
(q) 7 
(C) The distance of the point (1, 0, −3) from the plane x − y − z − 9 = 0 measured parallel to the line
(x - 2)/2 = (y + 2)/3 = (z - 6)/- 6 is
(r) 10/(3√3)
(D) The distance of the line 
(x - 2)/1 = (y + 2)/-1 = (z - 3)/4
from the plane x + 5y + z − 5 = 0 is
(s) 10/3
(t) 13/7

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1 Answer

+1 vote
by (57.6k points)
edited by

Correct match is (A) (t); (B)  (p); (C) (q); (D) → (r)

(A) - (t) 13/7

(B) - (p) √105

(C) - (q) 7

(D) - (r) 10/(3√3)

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