Let In = ∫ (sin nx/ sin x) dx
= ∫ ( 2cos(n – 1)x + (sin(n – 2)x)/ sin x) dx
[ ∵ sin nx – sin(n – 2)x = 2cos(n – 1) x sin x
(sin nx/ sinx) = 2cos(n – 1)x + (sin(n – 2)x)/ sin x) ]
(2 sin(n – 1)x)/ (n – 1)) + In – 2
which is the required reduction formula.