A transformer has turns ratio of 4:1 . What is the peak secondary voltage if 115 vrms is applied to the primary winding

Question

A transformer has a turns ratio of 4:1. What is the peak secondary voltage if 115 V rms is applied to the primary winding?

Answer 1

For Transformer the turn's ratio is given as N₁/N₂=4:1.

The voltage of the primary winding is V₁ = 115 Vrms.

We know that 

RMS Voltage Equation

The peak secondary voltage is given by

V₂ = N₂V₁/N₁

=1/4 x 115/0.707

= 40.6647

or = 40.67 V