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asked ago in Physics by (27 points)
A transformer has a turns ratio of 4:1. What is the peak secondary voltage if 115 V rms is applied to the primary winding?

1 Answer

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answered ago by (1k points)

For Transformer the turn's ratio is given as N1/N2=4:1.

The voltage of the primary winding is V1 = 115 Vrms.

We know that 

RMS Voltage Equation

RMS Voltage Formula

The peak secondary voltage is given by

V2 = N2V1/N1

=1/4 x 115/0.707

= 40.6647

or = 40.67 V

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