Correct option (a),(b),(c),(d)
Explanation :
See Fig. Let P be (cos θ, sinθ). The normal at P is
ax/cosθ - by/sinθ = a2 - b2
Therefore
We have PF = CT = perpendicular distance of C from the tangent at P which is given by
Therefore
PG.pg = SP.S'P
(d) We have