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+1 vote
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in Mathematics by (53.5k points)

The locus of the midpoint of the portion of the tangent to the ellipse x2/a2 +  y2/b2 = 1 included between the axes is the curve a2/x2 + b2/y2 = k where k is equal to ........

1 Answer

+1 vote
by (53.3k points)
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Best answer

The tangent at (a cos θ, b sin θ)  to the ellipse is

x/a cosθ + y/b sin θ = 1

This meets the axes at the points A(a sec θ , 0) and B(0, b cosec θ). Let (x1, y1) be the midpoint of  (bar)AB. Therefore

Therefore, the locus of (x1, x2) is

a2/x2 + b2/y2 = 4

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