Correct option (d)
Explanation :
The given ellipse equation is
(x - 1)2 + 4(y - 2)2 = -13 + 1 + 16 = 4
⇒ (x - 1)2/4 + (y - 2)2 = 1
We have a2 = 4,b2 = 1. The eccentricity e is given by
1 = 4(1 - e2) ⇒ e = √3/2
The latus rectum is
2b2/2 = 2(1)/2 = 1
Hence, Statement (A) is true. Also, the ellipse is
X2/4 + Y2/1 = 1
where X = x - 1, Y = y - 2 , . The foci is
Hence, the distance between the foci is
(1 + √3) - (1 - √3) = 2√3
Hence, Statement (B) is not true. The sum of the focal distance is
SP + S' P = 2a = 2(2) = 4
Therefore, Statement (C) is true. The tangents at the vertices are x - 1 = ±2 or x = 3, -1. The line y = 3 meets these tangents at (3, 3) and (−1, 3). We have P = (3, 3) and Q = (-1,3)S = (1 + √3,2) Therefore
Slope of SP x Slope of SP
Therefore, (bar)PQ subtends right angle at the focus (1, +√3,2) and also at the other focus. Hence, Statement (D) is true.